Tips For Fixing Gcc Ignore Qualifiers Errors

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Error: Passing “const A” as “this” rejects the argument to “void A :: hi ()”.Qualifier [-fpermissive]

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I don’t understand why I am getting this error, I am not returning the problem, just passing the reference to the main object and that’s it.

  #include Class Apublicly:    avoid hello ()           std :: cout << "Hello." << std :: endl;    ;Class Bpublicly:    undo, get (const A & a)        Hey ();    ;Class Cpublicly:    invalid check (const A & a)        Bb;        b. get (s);    ;int main (int argc, char ** argv)    Aa;    AGAINST; CC. received);    Returns 0; 

I change it with constant precision, but then I try to call methods in the same method and I get the same error.

  #include Class Apublicly:    Sayha whitespace () const            Hey();        Peace();        Hello empty ()            std :: cout << "world" << std :: endl;        Undo the world ()            std :: cout << "world" << std :: endl;    ;Class Bpublicly:    invalid check (const A & a)         a.sayhi ();    ;Class Cpublicly:    obtained unnecessarily (const A & a)        Bb;        b. get (s);    ;int main (int argc, char ** argv)    Aa;    AGAINST; CC. received);    return 0; 

Error: Passing const A as the this argument to void A :: hello ()remove qualifiers [-fpermissive]

Error: 'const A' as argument 'this' from 'void A :: world ()' completed successfullyremove qualifiers [-fpermissive]

wanted 16 Nov 14 at 23:54

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Not The Answer You Are Looking For? Check Out The Other Questions Tagged C ++, Or Post Your Own Question If You Wish.

Your hi formula is not declared due to const in your class A. Therefore, the compiler cannot guarantee that choosing a.Will hi ( ) change something related to a , so an error will be thrown.

More information on constant member functions can be found here.

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answered Nov 17 '14 at 0:00

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1. As mentioned earlier, one way to do this is to make the hi method const-qualified.

2. Another possibility was to use const_cast when calling the hi

   method

  A & ref Const_cast =  (a);ref.hi (); 

Reply sent on January 21

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John Anthony

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