You Have A Problem With The Error Url Java.net.bindexception Which Is Already In Use Cannot Bind

October 25, 2021 By David Serisier Off

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In the past few days, some users have come across an error message with the java.net.bindexception error address already in use without any obligation. This problem occurs for several reasons. Now let’s talk about some of them.

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g.BindException class Reports only that an error occurred while trying to bind a socket to a local address and port. Typically, a connector is used or the specified local address is not assigned.

I am following UDP video at http://docs.oracle.com/javase/tutorial/networking/datagrams/broadcasting.html, I copied and compiled every code here when I first compile client and then server. node prints this console

  Exception when appearing in the "main" thread java.net.Address Binding Exception: Already in use: Binding is not possibleunder java.net.PlainDatagramSocketImpl.bind0 (native method)at java.net.PlainDatagramSocketImpl.bind (source unknown)nand java.net.DatagramSocket.bind (source unknown)at java.net.DatagramSocket.  (source unknown)at java.net.DatagramSocket.  (source unknown)at java.net.DatagramSocket.  (source unknown)at QuoteServerThread.  (QuoteServerThread.java:19)in MulticastServerThread.  (MulticastServerThread.java:10)at MulticastServer.main (MulticastServer.java:3)

  socket = new DatagramSocket (12345);

  public MulticastServerThread () throws an IOException    super ("MulticastServerThread"); // selection 10

  public class MulticastServer    public static nullify main (String [] args) throws java.io.IOException        Modern MulticastServerThread () .start (); // line 3

When I first launch the site, the client reports this to the console

  Exception here in "main" thread java.net.Address bindException: Already in use: Unable to bindunder java.net.PlainDatagramSocketImpl.bind0 (native method)at java.net.PlainDatagramSocketImpl.bind (source unknown)at java.net.DatagramSocket.bind (source unknown)at java.net.MulticastSocket.  (source unknown)at java.net.MulticastSocket.  (source unknown)at MulticastClient.main (MulticastClient.java:9)

  MulticastSocket = new MulticastSocket (12345);

When I look at errors, it seems to me that this is what helpsIt lets you spy on ports. How can I deal with this?

People .. i am trying to write a client schema server with udp packages and udp socket. Here is my client code

 FileInputStream end;DatagramSocket client = null;DatagramPacket pkt = null;Inet address inet;int port = 9899;Try{String hname = System.getProperty ("Hostname");InetAddress-Adresse = InetAddress.getByName (hname);client = new DatagramSocket (port, address);File f = new file ("C: /sample.txt");end = new FileInputStream (f);long l = f.length ();byte [] buf = new byte [(int) l];end.read (buff);pkt = new DatagramPacket (buf, buf.length, address, port);client.send (pkt);

 serverocket = new DatagramSocket (9899);DatagramPackage rp =             new DatagramPacket (rdata, rdata.length);           serverocket.receive (rp);           byte [] file = rp.getData ();          UploadedFile is the same as the new file ("C: /responce.txt");uploadedFile.createNewFile ();outFile = new file ("C: /responce.txt");BufferedOutputStream product = new FileOutputStream (outFile));Bufferedoutputstream (new.write (file, 0, file.length);

I am sending a single byte [] to the server here and the server writes the following to a file BUT I get an exception
java.net.Address bindException: Already starts with: Unable to bind
at java.net.PlainDatagramSocketImpl.bind0 (native method)
at java.net.PlainDatagramSocketImpl.bind (PlainDatagramSocketImpl.java:82)
at java.net.DatagramSocket.bind (DatagramSocket.java:368)
at java.net.DatagramSocket. (DatagramSocket.java:210)
at java.net.DatagramSocket. (DatagramSocket.java:261)
at Client.main (Client.java:33)

Please note, I am using the checked one that I am NOT porting twice … the program returns an error on the line where I get the actual hostname InetAddress

If you are working with TCP / UDP sockets in JAVA, also you have probably seen an exception like the one below when trying to create a new socket on a specific specific port number instead of dynamically executing the assigned port number.

  Exception at location "main" java.net.Address bindException: Already in use (bind failed)under java.net.PlainDatagramSocketImpl.bind0 (native method)at java.net.AbstractPlainDatagramSocketImpl.bind (AbstractPlainDatagramSocketImpl.java:93)at java.net.DatagramSocket.bind (DatagramSocket.java:392)at java.net.DatagramSocket.  (DatagramSocket.java:242)at java.net.DatagramSocket.  (DatagramSocket.java:299)at java.net.DatagramSocket.  (DatagramSocket.java:271)at DatagramReceiverServer.main (DatagramReceiverServer.java:9)

Here we have used the DatagramReceiverServer.java example from JAVA DatagramSocket and Client Server Example as a great example. If we compile the Java code in the following paragraphs and run it Once from one terminal, and then fatally run the same program from another, we will get an exception similar to the one above in the second critical one.

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The program may throw the above exception if it is executed twice

  import java.net.DatagramPacket;import java.net.DatagramSocket;public class DatagramReceiverServer        private static int remoteServerPort is 1900;        static public useless main (String [] args) throws an exception                DatagramSocket localServerSocket = another DatagramSocket (remoteServerPort);                byte [] buf means new byte [1024];                DatagramPacket datagramReceiverPacket = new DatagramPacket (buf, 1024);                localServerSocket.receive (datagramReceiverPacket);                String ReceivedMessage = new line (datagramReceiverPacket.getData (), 0, datagramReceiverPacket.getLength ());               System .out.println (received message);                localServerSocket.close ();

Solution – The program has been modified so that each of our systems can assign a dynamic port every time we run this program.

  import java.net.DatagramPacket;import java.net.DatagramSocket;public sort DatagramReceiverServer        int stationary private remoteServerPort = 0;The old public void main (String [] args) throws an exception.                DatagramSocket localServerSocket = new DatagramSocket ();                remoteServerPort = localServerSocket.getLocalPort ();                System.out.Running println ("Server on port: inches + remote server-port);                byte [] buf = new byte [1024];                DatagramPacket datagramReceiverPacket = new DatagramPacket (buf, 1024);                localServerSocket.receive (datagramReceiverPacket);                String ReceivedMessage = modern string (datagramReceiverPacket.getData (), 0, datagramReceiverPacket.getLength ());               System .out.println (received message);                localServerSocket.close ();

In the above program, only the linear software we have changed is using an important port, like

  private static int remoteServerPort is 0;DatagramSocket localServerSocket = new DatagramSocket ();remoteServerPort corresponds to localServerSocket.getLocalPort ();System.out.println ("Server is running on port: inside + remoteServerPort);

Note. If you are not always sure which other resume is using the same port as yours, see “Determine which / process is using which port or will be busy for Android”. “. / Linuxâ €

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3.1. Expand the conflict. In this case, we all need to know which application is using the port.3.2. Start the server on a different port.3.3. Kill the current service.

Use netstat -a -o -n to check the estimated port usage.Use taskkill / F / PID to kill this process.

BindException is an exception that is thrown when binding fails when an application tries to bind a socket to a specific local address and port.